18x^2+9x-35=-

Solution for 18x^2+9x-35=- equation:

18x^2+9x-35=-

We move all terms to the left:

18x^2+9x-35-(-)=0

We add all the numbers together, and all the variables

18x^2+9x-35-0=0

We add all the numbers together, and all the variables

18x^2+9x-35=0

a = 18; b = 9; c = -35;
Δ = b2-4ac
Δ = 92-4·18·(-35)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-51}{2*18}=\frac{-60}{36}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+51}{2*18}=\frac{42}{36}
=1+1/6
$